Introduction to Derivatives: Rate of Change and Slopes


Motivation: Why Study Rate of Change?

Imagine you're driving a car. Your average speed from one town to another might be 60 km/h. But at a given moment — say, when a police radar checks you — your instantaneous speed might be 72 km/h.

This difference is key in calculus:

Derivatives measure how fast something is changing at a single moment — not just over an interval.


The Big Idea: From Average to Instantaneous Rate of Change

In algebra, we learned how to compute the slope between two points:

Average Rate of Change=f(x2)−f(x1)x2−x1\text{Average Rate of Change} = \frac{f(x_2) - f(x_1)}{x_2 - x_1}

But what if we want the rate of change at exactly one point?
We need a new idea — a limit — which leads to the derivative.


Connecting to Graphs: Secant and Tangent Lines

As the two points of the secant get closer together, the secant line becomes the tangent line.


Interactive Example: Average Speed Between Two Times

We define a position function:

s(t)=t3−2t2−t+3s(t) = t^3 - 2t^2 - t + 3

It models a moving object's position over time.

Use the sliders below to choose a starting and ending time (t0t_0 and t1t_1) to see:

As you bring t0t_0 and t1t_1 closer, the red secant line approaches the tangent line.

Interactive Graph

Move the sliders to explore how the average rate of change behaves!

Interactive Average Speed

t₀ = 1.0, t₁ = 3.0
Average speed (slope) = ?
Line equation: y = mt + b

Additional Example: A Leaking Water Tank

Scenario 1: Constant Leak

Suppose a tank leaks water at a steady rate of 2 liters per minute.

V(t)=100−2tV(t) = 100 - 2t

This is a linear function. The slope (rate) is always the same. We don’t even need calculus to describe how fast it's leaking — the rate of change is already constant.


Scenario 2: Increasing Leak (Crack Worsens Over Time)

Now suppose the leak gets worse over time — the more water that escapes, the faster it leaks.

V(t)=100−t2V(t) = 100 - t^2

Now the leak starts slowly, but over time the rate of leakage increases.

Let’s compute average rates:

Even though both intervals are 2 minutes long, the tank is losing water more quickly later on.
This is where derivatives shine — they tell us exactly how fast the leak is worsening at any moment.


Summary of Concepts

Concept Description
Average Rate of Change Slope between two points on a curve
Instantaneous Rate Slope at a single point (the derivative)
Secant Line Line connecting two points on the curve
Tangent Line Line just touching the curve at one point

Practice Exercises

1. Estimating Speed of a Thrown Ball

A ball’s height after tt seconds is:

h(t)=−5t2+20th(t) = -5t^2 + 20t


2. Table of Values (Function: f(x)=x2f(x) = x^2)

x f(x)
1 1
1.5 2.25
2 4

3. Graph-Based Estimation

A function f(x)f(x) (e.g. x2x^2) is plotted.


4. Real-Life Scenario

A runner covers:


5. Conceptual Challenge: Constant Acceleration

A car’s speed increases by 3 m/s every second.


Extra Advanced Exercises

1. Approaching the Instantaneous Rate with Limits

Let the position of an object be given by:

s(t)=t+1s(t) = \sqrt{t + 1}

Challenge: Try computing

s(3+h)−s(3)h\frac{s(3+h) - s(3)}{h}

for small values of $ h$ like 0.001,0.00010.001, 0.0001, and guess the limit as h→0h \to 0.


2. Sharp Corner Behavior

Let f(x)=∣x−2∣f(x) = |x - 2|


3. Multidimensional Rate

A balloon moves vertically and horizontally:

(a) Find the average vertical rate of change from t=2t = 2 to t=4t = 4.
(b) Compute total distance traveled.
(c) Estimate how fast the total distance is changing at t=3t = 3.


4. Instantaneous Rate from a Rational Function

Let the position of a car be given by:

s(t)=t2+3t+1t+1s(t) = \frac{t^2 + 3t + 1}{t + 1}


5. Function with Unpredictable Slope

Consider the function:

f(x)=x⋅sin⁡(1x),for x≠0,f(0)=0f(x) = x \cdot \sin\left(\frac{1}{x}\right), \quad \text{for } x \neq 0,\quad f(0) = 0

(a) Plot or sketch this function (use Desmos or another graphing tool)
(b) What happens to the slope of the secant line as x→0x \to 0?
(c) Can we estimate the slope at x=0x = 0? Why is this difficult?

Hint: This function is continuous at 0 but wildly oscillatory nearby.


Conclusion

In our next session, we’ll formally define the derivative using limits!

Recommendation:
Watch 3Blue1Brown's video on introdcution to derivatives and his series on calculus.